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1011019937953 is a prime number
BaseRepresentation
bin11101011011001010111…
…10111111100010100001
310120122121201101021110011
432231211132333202201
5113031032101003303
62052242310004521
7133021005452014
oct16554536774241
93518551337404
101011019937953
1135a853441433
12143b38646741
137445338429c
1436d0dc2737b
151b473e4316d
hexeb657bf8a1

1011019937953 has 2 divisors, whose sum is σ = 1011019937954. Its totient is φ = 1011019937952.

The previous prime is 1011019937947. The next prime is 1011019938001. The reversal of 1011019937953 is 3597399101101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 995938133089 + 15081804864 = 997967^2 + 122808^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011019937953 - 213 = 1011019929761 is a prime.

It is a super-2 number, since 2×10110199379532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011019937897 and 1011019937906.

It is not a weakly prime, because it can be changed into another prime (1011019937903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505509968976 + 505509968977.

It is an arithmetic number, because the mean of its divisors is an integer number (505509968977).

Almost surely, 21011019937953 is an apocalyptic number.

It is an amenable number.

1011019937953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011019937953 is an equidigital number, since it uses as much as digits as its factorization.

1011019937953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 229635, while the sum is 49.

The spelling of 1011019937953 in words is "one trillion, eleven billion, nineteen million, nine hundred thirty-seven thousand, nine hundred fifty-three".