1011021220123 has 2 divisors, whose sum is σ = 1011021220124. Its totient is φ = 1011021220122.

The previous prime is 1011021220067. The next prime is 1011021220127. The reversal of 1011021220123 is 3210221201101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011021220123 - 2²⁹ = 1010484349211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011021220097 and 1011021220106.

It is not a weakly prime, because it can be changed into another prime (1011021220127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505510610061 + 505510610062.

It is an arithmetic number, because the mean of its divisors is an integer number (505510610062).

Almost surely, 2^{1011021220123} is an apocalyptic number.

1011021220123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011021220123 is an equidigital number, since it uses as much as digits as its factorization.

1011021220123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1011021220123 its reverse (3210221201101), we get a palindrome (4221242421224).

The spelling of 1011021220123 in words is "one trillion, eleven billion, twenty-one million, two hundred twenty thousand, one hundred twenty-three".