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101102241403 = 731384962211
BaseRepresentation
bin101111000101000101…
…0011100011001111011
3100122221222201000012101
41132022022130121323
53124024133211103
6114240135524231
710206256605202
oct1361212343173
9318858630171
10101102241403
1139971641409
1217716b29677
1396c2c966a7
144c715c4239
15296adb4a1d
hex178a29c67b

101102241403 has 4 divisors (see below), whose sum is σ = 102487203688. Its totient is φ = 99717279120.

The previous prime is 101102241347. The next prime is 101102241463. The reversal of 101102241403 is 304142201101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304142201101 = 2281133337221.

It is a cyclic number.

It is not a de Polignac number, because 101102241403 - 29 = 101102240891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101102241463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692481033 + ... + 692481178.

It is an arithmetic number, because the mean of its divisors is an integer number (25621800922).

Almost surely, 2101102241403 is an apocalyptic number.

101102241403 is a deficient number, since it is larger than the sum of its proper divisors (1384962285).

101102241403 is an equidigital number, since it uses as much as digits as its factorization.

101102241403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1384962284.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 101102241403 its reverse (304142201101), we get a palindrome (405244442504).

The spelling of 101102241403 in words is "one hundred one billion, one hundred two million, two hundred forty-one thousand, four hundred three".

Divisors: 1 73 1384962211 101102241403