Base | Representation |
---|---|
bin | 1001001100011111111000… |
… | …1110010100000111111001 |
3 | 1022210112111210211010210122 |
4 | 2103013332032110013321 |
5 | 2311121420220302133 |
6 | 33300341322223025 |
7 | 2062306143234146 |
oct | 223077616240771 |
9 | 38715453733718 |
10 | 10110323212793 |
11 | 3248844972741 |
12 | 1173546954a75 |
13 | 5845265bcaab |
14 | 26d4b12093cd |
15 | 127ed55d2498 |
hex | 931fe3941f9 |
10110323212793 has 2 divisors, whose sum is σ = 10110323212794. Its totient is φ = 10110323212792.
The previous prime is 10110323212721. The next prime is 10110323212817. The reversal of 10110323212793 is 39721232301101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9791310617449 + 319012595344 = 3129107^2 + 564812^2 .
It is a cyclic number.
It is not a de Polignac number, because 10110323212793 - 222 = 10110319018489 is a prime.
It is not a weakly prime, because it can be changed into another prime (10110323214793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055161606396 + 5055161606397.
It is an arithmetic number, because the mean of its divisors is an integer number (5055161606397).
Almost surely, 210110323212793 is an apocalyptic number.
It is an amenable number.
10110323212793 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110323212793 is an equidigital number, since it uses as much as digits as its factorization.
10110323212793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 35.
Adding to 10110323212793 its reverse (39721232301101), we get a palindrome (49831555513894).
The spelling of 10110323212793 in words is "ten trillion, one hundred ten billion, three hundred twenty-three million, two hundred twelve thousand, seven hundred ninety-three".
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