1011043343131 has 2 divisors, whose sum is σ = 1011043343132. Its totient is φ = 1011043343130.

The previous prime is 1011043343087. The next prime is 1011043343159. The reversal of 1011043343131 is 1313433401101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011043343131 - 2⁷ = 1011043343003 is a prime.

It is a super-2 number, since 2×1011043343131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011043343096 and 1011043343105.

It is not a weakly prime, because it can be changed into another prime (1011043343731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505521671565 + 505521671566.

It is an arithmetic number, because the mean of its divisors is an integer number (505521671566).

Almost surely, 2^{1011043343131} is an apocalyptic number.

1011043343131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011043343131 is an equidigital number, since it uses as much as digits as its factorization.

1011043343131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1011043343131 its reverse (1313433401101), we get a palindrome (2324476744232).

The spelling of 1011043343131 in words is "one trillion, eleven billion, forty-three million, three hundred forty-three thousand, one hundred thirty-one".