Search a number
-
+
1011100202083 is a prime number
BaseRepresentation
bin11101011011010100100…
…01001011010001100011
310120122211022102010010201
432231222101023101203
5113031213122431313
62052254254210031
7133023001625146
oct16555221132143
93518738363121
101011100202083
1135a894783024
12143b5b4b3917
1374466ba795a
1436d1a75c05d
151b47aeea0dd
hexeb6a44b463

1011100202083 has 2 divisors, whose sum is σ = 1011100202084. Its totient is φ = 1011100202082.

The previous prime is 1011100202051. The next prime is 1011100202117. The reversal of 1011100202083 is 3802020011101.

1011100202083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011100202083 - 25 = 1011100202051 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1011100202083.

It is not a weakly prime, because it can be changed into another prime (1011100202023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505550101041 + 505550101042.

It is an arithmetic number, because the mean of its divisors is an integer number (505550101042).

Almost surely, 21011100202083 is an apocalyptic number.

1011100202083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011100202083 is an equidigital number, since it uses as much as digits as its factorization.

1011100202083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1011100202083 its reverse (3802020011101), we get a palindrome (4813120213184).

The spelling of 1011100202083 in words is "one trillion, eleven billion, one hundred million, two hundred two thousand, eighty-three".