Base | Representation |
---|---|
bin | 11101011011010100100… |
… | …01001011010001100011 |
3 | 10120122211022102010010201 |
4 | 32231222101023101203 |
5 | 113031213122431313 |
6 | 2052254254210031 |
7 | 133023001625146 |
oct | 16555221132143 |
9 | 3518738363121 |
10 | 1011100202083 |
11 | 35a894783024 |
12 | 143b5b4b3917 |
13 | 74466ba795a |
14 | 36d1a75c05d |
15 | 1b47aeea0dd |
hex | eb6a44b463 |
1011100202083 has 2 divisors, whose sum is σ = 1011100202084. Its totient is φ = 1011100202082.
The previous prime is 1011100202051. The next prime is 1011100202117. The reversal of 1011100202083 is 3802020011101.
1011100202083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011100202083 - 25 = 1011100202051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1011100202083.
It is not a weakly prime, because it can be changed into another prime (1011100202023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505550101041 + 505550101042.
It is an arithmetic number, because the mean of its divisors is an integer number (505550101042).
Almost surely, 21011100202083 is an apocalyptic number.
1011100202083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011100202083 is an equidigital number, since it uses as much as digits as its factorization.
1011100202083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1011100202083 its reverse (3802020011101), we get a palindrome (4813120213184).
The spelling of 1011100202083 in words is "one trillion, eleven billion, one hundred million, two hundred two thousand, eighty-three".
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