Base | Representation |
---|---|
bin | 1001001100100010011100… |
… | …1110011011111111110001 |
3 | 1022210121021202012222121012 |
4 | 2103020213032123333301 |
5 | 2311124322321022042 |
6 | 33300533454240305 |
7 | 2062332165253034 |
oct | 223104716337761 |
9 | 38717252188535 |
10 | 10111011110897 |
11 | 32490681a6774 |
12 | 11736b91b6095 |
13 | 584605c829a8 |
14 | 26d53871301b |
15 | 128025bb3e82 |
hex | 9322739bff1 |
10111011110897 has 2 divisors, whose sum is σ = 10111011110898. Its totient is φ = 10111011110896.
The previous prime is 10111011110839. The next prime is 10111011110903. The reversal of 10111011110897 is 79801111011101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10104775797601 + 6235313296 = 3178801^2 + 78964^2 .
It is a cyclic number.
It is not a de Polignac number, because 10111011110897 - 230 = 10109937369073 is a prime.
It is a super-3 number, since 3×101110111108973 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10111011110797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055505555448 + 5055505555449.
It is an arithmetic number, because the mean of its divisors is an integer number (5055505555449).
Almost surely, 210111011110897 is an apocalyptic number.
It is an amenable number.
10111011110897 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111011110897 is an equidigital number, since it uses as much as digits as its factorization.
10111011110897 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 32.
Adding to 10111011110897 its reverse (79801111011101), we get a palindrome (89912122121998).
The spelling of 10111011110897 in words is "ten trillion, one hundred eleven billion, eleven million, one hundred ten thousand, eight hundred ninety-seven".
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