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101110211100131 is a prime number
BaseRepresentation
bin10110111111010110001110…
…001101110011110111100011
3111021000001010110100221002012
4112333112032031303313203
5101223042203020201011
6555013220103343135
730203654200610102
oct2677261615636743
9437001113327065
10101110211100131
112a2426662568a2
12b40ba05151aab
1344558625811ac
141ad7a904b0039
15ba519692ba8b
hex5bf58e373de3

101110211100131 has 2 divisors, whose sum is σ = 101110211100132. Its totient is φ = 101110211100130.

The previous prime is 101110211100091. The next prime is 101110211100161. The reversal of 101110211100131 is 131001112011101.

It is a strong prime.

It is an emirp because it is prime and its reverse (131001112011101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101110211100131 - 214 = 101110211083747 is a prime.

It is a super-2 number, since 2×1011102111001312 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (101110211100161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555105550065 + 50555105550066.

It is an arithmetic number, because the mean of its divisors is an integer number (50555105550066).

Almost surely, 2101110211100131 is an apocalyptic number.

101110211100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101110211100131 is an equidigital number, since it uses as much as digits as its factorization.

101110211100131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 14.

Adding to 101110211100131 its reverse (131001112011101), we get a palindrome (232111323111232).

The spelling of 101110211100131 in words is "one hundred one trillion, one hundred ten billion, two hundred eleven million, one hundred thousand, one hundred thirty-one".