Base | Representation |
---|---|
bin | 1001001100100010100001… |
… | …1110001111111101110011 |
3 | 1022210121100012120221112001 |
4 | 2103020220132033331303 |
5 | 2311124343200030024 |
6 | 33300535522514431 |
7 | 2062332541142602 |
oct | 223105036177563 |
9 | 38717305527461 |
10 | 10111032033139 |
11 | 3249078a96984 |
12 | 1173704205a17 |
13 | 58460a3c9b0b |
14 | 26d53b3dba39 |
15 | 128027948244 |
hex | 9322878ff73 |
10111032033139 has 2 divisors, whose sum is σ = 10111032033140. Its totient is φ = 10111032033138.
The previous prime is 10111032033103. The next prime is 10111032033173. The reversal of 10111032033139 is 93133023011101.
It is a strong prime.
It is an emirp because it is prime and its reverse (93133023011101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10111032033139 - 223 = 10111023644531 is a prime.
It is a super-3 number, since 3×101110320331393 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10111032033239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055516016569 + 5055516016570.
It is an arithmetic number, because the mean of its divisors is an integer number (5055516016570).
Almost surely, 210111032033139 is an apocalyptic number.
10111032033139 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111032033139 is an equidigital number, since it uses as much as digits as its factorization.
10111032033139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 10111032033139 in words is "ten trillion, one hundred eleven billion, thirty-two million, thirty-three thousand, one hundred thirty-nine".
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