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101111110999993 is a prime number
BaseRepresentation
bin10110111111010111000011…
…110110101001111110111001
3111021000010110011200120121201
4112333113003312221332321
5101223101023403444433
6555013445251334201
730204015405620623
oct2677270366517671
9437003404616551
10101111110999993
112a242a8821a996
12b4100165b1361
134455976b41113
141ad7b37c01c13
15ba51ea938a7d
hex5bf5c3da9fb9

101111110999993 has 2 divisors, whose sum is σ = 101111110999994. Its totient is φ = 101111110999992.

The previous prime is 101111110999883. The next prime is 101111111000063. The reversal of 101111110999993 is 399999011111101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95974782275584 + 5136328724409 = 9796672^2 + 2266347^2 .

It is a cyclic number.

It is not a de Polignac number, because 101111110999993 - 237 = 100973672046521 is a prime.

It is not a weakly prime, because it can be changed into another prime (101111110991993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555555499996 + 50555555499997.

It is an arithmetic number, because the mean of its divisors is an integer number (50555555499997).

Almost surely, 2101111110999993 is an apocalyptic number.

It is an amenable number.

101111110999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

101111110999993 is an equidigital number, since it uses as much as digits as its factorization.

101111110999993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 177147, while the sum is 55.

The spelling of 101111110999993 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, nine hundred ninety-nine thousand, nine hundred ninety-three".