Base | Representation |
---|---|
bin | 10010110101010110… |
… | …01101011001001011 |
3 | 222002200000202001101 |
4 | 21122223031121023 |
5 | 131201432223313 |
6 | 4351154202231 |
7 | 505364606341 |
oct | 113253153113 |
9 | 28080022041 |
10 | 10111211083 |
11 | 43195735a6 |
12 | 1b62283377 |
13 | c51a57b4c |
14 | 6bcc31991 |
15 | 3e2a295dd |
hex | 25aacd64b |
10111211083 has 2 divisors, whose sum is σ = 10111211084. Its totient is φ = 10111211082.
The previous prime is 10111211053. The next prime is 10111211161. The reversal of 10111211083 is 38011211101.
It is a weak prime.
It is an emirp because it is prime and its reverse (38011211101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10111211083 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10111211083.
It is not a weakly prime, because it can be changed into another prime (10111211053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055605541 + 5055605542.
It is an arithmetic number, because the mean of its divisors is an integer number (5055605542).
Almost surely, 210111211083 is an apocalyptic number.
10111211083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111211083 is an equidigital number, since it uses as much as digits as its factorization.
10111211083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 10111211083 its reverse (38011211101), we get a palindrome (48122422184).
The spelling of 10111211083 in words is "ten billion, one hundred eleven million, two hundred eleven thousand, eighty-three".
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