1011121312987 has 2 divisors, whose sum is σ = 1011121312988. Its totient is φ = 1011121312986.

The previous prime is 1011121312951. The next prime is 1011121313003. The reversal of 1011121312987 is 7892131211101.

It is a strong prime.

It is an emirp because it is prime and its reverse (7892131211101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011121312987 - 2¹⁵ = 1011121280219 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011121312937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560656493 + 505560656494.

It is an arithmetic number, because the mean of its divisors is an integer number (505560656494).

Almost surely, 2^{1011121312987} is an apocalyptic number.

1011121312987 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011121312987 is an equidigital number, since it uses as much as digits as its factorization.

1011121312987 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 37.

The spelling of 1011121312987 in words is "one trillion, eleven billion, one hundred twenty-one million, three hundred twelve thousand, nine hundred eighty-seven".