10111313209 has 2 divisors, whose sum is σ = 10111313210. Its totient is φ = 10111313208.

The previous prime is 10111313161. The next prime is 10111313237. The reversal of 10111313209 is 90231311101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10111308025 + 5184 = 100555^2 + 72^2 .

It is an emirp because it is prime and its reverse (90231311101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111313209 - 2⁹ = 10111312697 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10111313209.

It is not a weakly prime, because it can be changed into another prime (10111313299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055656604 + 5055656605.

It is an arithmetic number, because the mean of its divisors is an integer number (5055656605).

Almost surely, 2^10111313209 is an apocalyptic number.

It is an amenable number.

10111313209 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111313209 is an equidigital number, since it uses as much as digits as its factorization.

10111313209 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 10111313209 in words is "ten billion, one hundred eleven million, three hundred thirteen thousand, two hundred nine".