101113433050 has 84 divisors (see below), whose sum is σ = 219428648190. Its totient is φ = 34665445920.

The previous prime is 101113433023. The next prime is 101113433077. The reversal of 101113433050 is 50334311101.

It is an interprime number because it is at equal distance from previous prime (101113433023) and next prime (101113433077).

It can be written as a sum of positive squares in 3 ways, for example, as 93819077401 + 7294355649 = 306299^2 + 85407^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 41 ways as a sum of consecutive naturals, for example, 5873856 + ... + 5891044.

Almost surely, 2^101113433050 is an apocalyptic number.

101113433050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101113433050 is an abundant number, since it is smaller than the sum of its proper divisors (118315215140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101113433050 is an frugal number, since it uses more digits than its factorization.

101113433050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17243 (or 17203 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 101113433050 its reverse (50334311101), we get a palindrome (151447744151).

The spelling of 101113433050 in words is "one hundred one billion, one hundred thirteen million, four hundred thirty-three thousand, fifty".