101115137 has 2 divisors, whose sum is σ = 101115138. Its totient is φ = 101115136.

The previous prime is 101115109. The next prime is 101115173. The reversal of 101115137 is 731511101.

Together with next prime (101115173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68293696 + 32821441 = 8264^2 + 5729^2 .

It is an emirp because it is prime and its reverse (731511101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101115137 - 2⁶ = 101115073 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101115197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50557568 + 50557569.

It is an arithmetic number, because the mean of its divisors is an integer number (50557569).

Almost surely, 2^101115137 is an apocalyptic number.

It is an amenable number.

101115137 is a deficient number, since it is larger than the sum of its proper divisors (1).

101115137 is an equidigital number, since it uses as much as digits as its factorization.

101115137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105, while the sum is 20.

The square root of 101115137 is about 10055.6022693820. The cubic root of 101115137 is about 465.8778453296.

Adding to 101115137 its reverse (731511101), we get a palindrome (832626238).

The spelling of 101115137 in words is "one hundred one million, one hundred fifteen thousand, one hundred thirty-seven".