Search a number
-
+
101120210210122 = 250560105105061
BaseRepresentation
bin10110111111011111100010…
…001101011000110101001010
3111021000222221022110100100021
4112333133202031120311022
5101223223142303210442
6555021552215131054
730204460034624215
oct2677374215306512
9437028838410307
10101120210210122
112a246927513164
12b411935973a8a
13445679701951c
141ad835c48077c
15ba557e6b0e67
hex5bf7e2358d4a

101120210210122 has 4 divisors (see below), whose sum is σ = 151680315315186. Its totient is φ = 50560105105060.

The previous prime is 101120210210051. The next prime is 101120210210209. The reversal of 101120210210122 is 221012012021101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 60640343670481 + 40479866539641 = 7787191^2 + 6362379^2 .

It is a super-3 number, since 3×1011202102101223 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101120210210096 and 101120210210105.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25280052552529 + ... + 25280052552532.

Almost surely, 2101120210210122 is an apocalyptic number.

101120210210122 is a deficient number, since it is larger than the sum of its proper divisors (50560105105064).

101120210210122 is an equidigital number, since it uses as much as digits as its factorization.

101120210210122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50560105105063.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 101120210210122 its reverse (221012012021101), we get a palindrome (322132222231223).

The spelling of 101120210210122 in words is "one hundred one trillion, one hundred twenty billion, two hundred ten million, two hundred ten thousand, one hundred twenty-two".

Divisors: 1 2 50560105105061 101120210210122