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101121000000 = 2635637911
BaseRepresentation
bin101111000101101001…
…0000000001001000000
3100200000022000001011020
41132023102000021000
53124043434000000
6114242045545440
710206605214036
oct1361322001100
9320008001136
10101121000000
1139981193a89
1217721275280
1396c6b33a57
144c73ca8556
15296c86cba0
hex178b480240

101121000000 has 392 divisors, whose sum is σ = 343848098688. Its totient is φ = 26208000000.

The previous prime is 101120999999. The next prime is 101121000053. The reversal of 101121000000 is 121101.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 110999545 + ... + 111000455.

Almost surely, 2101121000000 is an apocalyptic number.

101121000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101121000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (171924049344).

101121000000 is an abundant number, since it is smaller than the sum of its proper divisors (242727098688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101121000000 is an frugal number, since it uses more digits than its factorization.

101121000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 993 (or 958 counting only the distinct ones).

The product of its (nonzero) digits is 2, while the sum is 6.

Adding to 101121000000 its reverse (121101), we get a palindrome (101121121101).

The spelling of 101121000000 in words is "one hundred one billion, one hundred twenty-one million", and thus it is an aban number.