Base | Representation |
---|---|
bin | 10010110101011101… |
… | …01001010111100001 |
3 | 222002201201112000021 |
4 | 21122232221113201 |
5 | 131202200041342 |
6 | 4351225353441 |
7 | 505405351243 |
oct | 113256512741 |
9 | 28081645007 |
10 | 10112112097 |
11 | 431a02953a |
12 | 1b62638881 |
13 | c51cb1ca9 |
14 | 6bcdc8093 |
15 | 3e2b56567 |
hex | 25aba95e1 |
10112112097 has 2 divisors, whose sum is σ = 10112112098. Its totient is φ = 10112112096.
The previous prime is 10112112089. The next prime is 10112112107. The reversal of 10112112097 is 79021121101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5447768481 + 4664343616 = 73809^2 + 68296^2 .
It is a cyclic number.
It is not a de Polignac number, because 10112112097 - 23 = 10112112089 is a prime.
It is a super-2 number, since 2×101121120972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10112110097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056056048 + 5056056049.
It is an arithmetic number, because the mean of its divisors is an integer number (5056056049).
Almost surely, 210112112097 is an apocalyptic number.
It is an amenable number.
10112112097 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112112097 is an equidigital number, since it uses as much as digits as its factorization.
10112112097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
Adding to 10112112097 its reverse (79021121101), we get a palindrome (89133233198).
The spelling of 10112112097 in words is "ten billion, one hundred twelve million, one hundred twelve thousand, ninety-seven".
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