Base | Representation |
---|---|
bin | 11101011011100001111… |
… | …00011010100001110011 |
3 | 10120200010010011012110121 |
4 | 32231300330122201303 |
5 | 113031430310400201 |
6 | 2052313334511111 |
7 | 133025531610634 |
oct | 16556074324163 |
9 | 3520103135417 |
10 | 1011212200051 |
11 | 35a941a19829 |
12 | 143b90b05497 |
13 | 7448415c541 |
14 | 36d2b59388b |
15 | 1b485c6e9a1 |
hex | eb70f1a873 |
1011212200051 has 2 divisors, whose sum is σ = 1011212200052. Its totient is φ = 1011212200050.
The previous prime is 1011212200039. The next prime is 1011212200091. The reversal of 1011212200051 is 1500022121101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011212200051 - 213 = 1011212191859 is a prime.
It is a super-2 number, since 2×10112122000512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1011212199998 and 1011212200034.
It is not a weakly prime, because it can be changed into another prime (1011212200091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505606100025 + 505606100026.
It is an arithmetic number, because the mean of its divisors is an integer number (505606100026).
Almost surely, 21011212200051 is an apocalyptic number.
1011212200051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011212200051 is an equidigital number, since it uses as much as digits as its factorization.
1011212200051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 1011212200051 its reverse (1500022121101), we get a palindrome (2511234321152).
The spelling of 1011212200051 in words is "one trillion, eleven billion, two hundred twelve million, two hundred thousand, fifty-one".
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