Base | Representation |
---|---|
bin | 1001001100100110101000… |
… | …0111010000101011011001 |
3 | 1022210201011221211020202201 |
4 | 2103021222013100223121 |
5 | 2311134122111144001 |
6 | 33301241102530201 |
7 | 2062402042605112 |
oct | 223115207205331 |
9 | 38721157736681 |
10 | 10112133303001 |
11 | 3249593699264 |
12 | 1173970b96961 |
13 | 5847546037a2 |
14 | 26d60378b209 |
15 | 12808e480501 |
hex | 9326a1d0ad9 |
10112133303001 has 2 divisors, whose sum is σ = 10112133303002. Its totient is φ = 10112133303000.
The previous prime is 10112133302899. The next prime is 10112133303007. The reversal of 10112133303001 is 10030333121101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10059198797376 + 52934505625 = 3171624^2 + 230075^2 .
It is a cyclic number.
It is not a de Polignac number, because 10112133303001 - 223 = 10112124914393 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10112133303001.
It is not a weakly prime, because it can be changed into another prime (10112133303007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056066651500 + 5056066651501.
It is an arithmetic number, because the mean of its divisors is an integer number (5056066651501).
Almost surely, 210112133303001 is an apocalyptic number.
It is an amenable number.
10112133303001 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112133303001 is an equidigital number, since it uses as much as digits as its factorization.
10112133303001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 10112133303001 its reverse (10030333121101), we get a palindrome (20142466424102).
The spelling of 10112133303001 in words is "ten trillion, one hundred twelve billion, one hundred thirty-three million, three hundred three thousand, one".
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