Base | Representation |
---|---|
bin | 1001001100100110111010… |
… | …1111101100001000000011 |
3 | 1022210201101101001011210121 |
4 | 2103021232233230020003 |
5 | 2311134302004310201 |
6 | 33301252520241111 |
7 | 2062404005241223 |
oct | 223115657541003 |
9 | 38721341034717 |
10 | 10112211010051 |
11 | 3249623543767 |
12 | 1173993010197 |
13 | 5847677402a7 |
14 | 26d60dc18083 |
15 | 1280961ce9a1 |
hex | 9326ebec203 |
10112211010051 has 2 divisors, whose sum is σ = 10112211010052. Its totient is φ = 10112211010050.
The previous prime is 10112211010019. The next prime is 10112211010117. The reversal of 10112211010051 is 15001011221101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10112211010051 - 25 = 10112211010019 is a prime.
It is not a weakly prime, because it can be changed into another prime (10112211010151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056105505025 + 5056105505026.
It is an arithmetic number, because the mean of its divisors is an integer number (5056105505026).
Almost surely, 210112211010051 is an apocalyptic number.
10112211010051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112211010051 is an equidigital number, since it uses as much as digits as its factorization.
10112211010051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 16.
Adding to 10112211010051 its reverse (15001011221101), we get a palindrome (25113222231152).
The spelling of 10112211010051 in words is "ten trillion, one hundred twelve billion, two hundred eleven million, ten thousand, fifty-one".
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