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10112220113 is a prime number
BaseRepresentation
bin10010110101011110…
…00011101111010001
3222002201221000011212
421122233003233101
5131202212020423
64351231545505
7505406311202
oct113257035721
928081830155
1010112220113
11431a0a2706
121b6268b295
13c5201c1c8
146bd0155a9
153e2b78578
hex25abc3bd1

10112220113 has 2 divisors, whose sum is σ = 10112220114. Its totient is φ = 10112220112.

The previous prime is 10112220103. The next prime is 10112220149. The reversal of 10112220113 is 31102221101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9302988304 + 809231809 = 96452^2 + 28447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10112220113 is a prime.

It is a super-2 number, since 2×101122201132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10112220103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056110056 + 5056110057.

It is an arithmetic number, because the mean of its divisors is an integer number (5056110057).

Almost surely, 210112220113 is an apocalyptic number.

It is an amenable number.

10112220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112220113 is an equidigital number, since it uses as much as digits as its factorization.

10112220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10112220113 its reverse (31102221101), we get a palindrome (41214441214).

The spelling of 10112220113 in words is "ten billion, one hundred twelve million, two hundred twenty thousand, one hundred thirteen".