Base | Representation |
---|---|
bin | 10010110101011110… |
… | …11010011010101011 |
3 | 222002202002201121020 |
4 | 21122233122122223 |
5 | 131202223004003 |
6 | 4351233543523 |
7 | 505410146052 |
oct | 113257323253 |
9 | 28082081536 |
10 | 10112313003 |
11 | 431a156481 |
12 | 1b62714ba3 |
13 | c52052580 |
14 | 6bd03b399 |
15 | 3e2b95d53 |
hex | 25abda6ab |
10112313003 has 16 divisors (see below), whose sum is σ = 14758284576. Its totient is φ = 6120944640.
The previous prime is 10112312971. The next prime is 10112313007. The reversal of 10112313003 is 30031321101.
It is not a de Polignac number, because 10112313003 - 25 = 10112312971 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10112313007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2122950 + ... + 2127707.
It is an arithmetic number, because the mean of its divisors is an integer number (922392786).
Almost surely, 210112313003 is an apocalyptic number.
10112313003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
10112313003 is a deficient number, since it is larger than the sum of its proper divisors (4645971573).
10112313003 is a wasteful number, since it uses less digits than its factorization.
10112313003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4250734.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10112313003 its reverse (30031321101), we get a palindrome (40143634104).
The spelling of 10112313003 in words is "ten billion, one hundred twelve million, three hundred thirteen thousand, three".
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