Base | Representation |
---|---|
bin | 1001001100100111010011… |
… | …1001010100110010000011 |
3 | 1022210201122120012201122212 |
4 | 2103021310321110302003 |
5 | 2311140004413333141 |
6 | 33301311044052335 |
7 | 2062406400315152 |
oct | 223116471246203 |
9 | 38721576181585 |
10 | 10112314199171 |
11 | 3249676813228 |
12 | 1173a016940ab |
13 | 584782c2c542 |
14 | 26d61d7d9599 |
15 | 1280a02b42eb |
hex | 93274e54c83 |
10112314199171 has 2 divisors, whose sum is σ = 10112314199172. Its totient is φ = 10112314199170.
The previous prime is 10112314199137. The next prime is 10112314199231. The reversal of 10112314199171 is 17199141321101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10112314199171 - 230 = 10111240457347 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10112314192171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056157099585 + 5056157099586.
It is an arithmetic number, because the mean of its divisors is an integer number (5056157099586).
Almost surely, 210112314199171 is an apocalyptic number.
10112314199171 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112314199171 is an equidigital number, since it uses as much as digits as its factorization.
10112314199171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 41.
The spelling of 10112314199171 in words is "ten trillion, one hundred twelve billion, three hundred fourteen million, one hundred ninety-nine thousand, one hundred seventy-one".
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