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10112321333131 is a prime number
BaseRepresentation
bin1001001100100111010101…
…0100100010011110001011
31022210201200001122011121121
42103021311110202132023
52311140013230130011
633301311501020111
72062406515046653
oct223116524423613
938721601564547
1010112321333131
11324967a846066
121173a03b54637
13584784559714
1426d620735363
151280a0c22e71
hex9327552278b

10112321333131 has 2 divisors, whose sum is σ = 10112321333132. Its totient is φ = 10112321333130.

The previous prime is 10112321333083. The next prime is 10112321333189. The reversal of 10112321333131 is 13133312321101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10112321333131 - 215 = 10112321300363 is a prime.

It is a super-2 number, since 2×101123213331312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10112321333096 and 10112321333105.

It is not a weakly prime, because it can be changed into another prime (10112321333431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056160666565 + 5056160666566.

It is an arithmetic number, because the mean of its divisors is an integer number (5056160666566).

Almost surely, 210112321333131 is an apocalyptic number.

10112321333131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112321333131 is an equidigital number, since it uses as much as digits as its factorization.

10112321333131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 10112321333131 its reverse (13133312321101), we get a palindrome (23245633654232).

The spelling of 10112321333131 in words is "ten trillion, one hundred twelve billion, three hundred twenty-one million, three hundred thirty-three thousand, one hundred thirty-one".