Base | Representation |
---|---|
bin | 11101011011100100011… |
… | …00001101111110000001 |
3 | 10120200011120112001102022 |
4 | 32231302030031332001 |
5 | 113032001134321004 |
6 | 2052315403131225 |
7 | 133026204461261 |
oct | 16556214157601 |
9 | 3520146461368 |
10 | 1011233120129 |
11 | 35a952808351 |
12 | 143b97b13b15 |
13 | 744885a569b |
14 | 36d3027b7a1 |
15 | 1b487a032be |
hex | eb7230df81 |
1011233120129 has 2 divisors, whose sum is σ = 1011233120130. Its totient is φ = 1011233120128.
The previous prime is 1011233120089. The next prime is 1011233120159. The reversal of 1011233120129 is 9210213321101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 988950691600 + 22282428529 = 994460^2 + 149273^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011233120129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011233120098 and 1011233120107.
It is not a weakly prime, because it can be changed into another prime (1011233120159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505616560064 + 505616560065.
It is an arithmetic number, because the mean of its divisors is an integer number (505616560065).
Almost surely, 21011233120129 is an apocalyptic number.
It is an amenable number.
1011233120129 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011233120129 is an equidigital number, since it uses as much as digits as its factorization.
1011233120129 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 1011233120129 in words is "one trillion, eleven billion, two hundred thirty-three million, one hundred twenty thousand, one hundred twenty-nine".
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