10112500001433 has 4 divisors (see below), whose sum is σ = 13483333335248. Its totient is φ = 6741666667620.

The previous prime is 10112500001423. The next prime is 10112500001467. The reversal of 10112500001433 is 33410000521101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10112500001433 - 2¹³ = 10112499993241 is a prime.

It is a super-3 number, since 3×10112500001433³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10112500001423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685416666903 + ... + 1685416666908.

It is an arithmetic number, because the mean of its divisors is an integer number (3370833333812).

Almost surely, 2^{10112500001433} is an apocalyptic number.

It is an amenable number.

10112500001433 is a deficient number, since it is larger than the sum of its proper divisors (3370833333815).

10112500001433 is an equidigital number, since it uses as much as digits as its factorization.

10112500001433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3370833333814.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 10112500001433 its reverse (33410000521101), we get a palindrome (43522500522534).

The spelling of 10112500001433 in words is "ten trillion, one hundred twelve billion, five hundred million, one thousand, four hundred thirty-three".