Base | Representation |
---|---|
bin | 11101011011101100011… |
… | …00100100111011000011 |
3 | 10120200100020222022102221 |
4 | 32231312030210323003 |
5 | 113032120340314021 |
6 | 2052330203351511 |
7 | 133030651625116 |
oct | 16556614447303 |
9 | 3520306868387 |
10 | 1011300323011 |
11 | 35a987738920 |
12 | 143bb6522597 |
13 | 744994a4cc4 |
14 | 36d3917257d |
15 | 1b48d87a241 |
hex | eb76324ec3 |
1011300323011 has 16 divisors (see below), whose sum is σ = 1109821769568. Its totient is φ = 913878380800.
The previous prime is 1011300322987. The next prime is 1011300323093. The reversal of 1011300323011 is 1103230031101.
It is not a de Polignac number, because 1011300323011 - 25 = 1011300322979 is a prime.
It is a super-2 number, since 2×10113003230112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1011300323711) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10718301 + ... + 10812241.
It is an arithmetic number, because the mean of its divisors is an integer number (69363860598).
Almost surely, 21011300323011 is an apocalyptic number.
1011300323011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1011300323011 is a deficient number, since it is larger than the sum of its proper divisors (98521446557).
1011300323011 is a wasteful number, since it uses less digits than its factorization.
1011300323011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99782.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1011300323011 its reverse (1103230031101), we get a palindrome (2114530354112).
The spelling of 1011300323011 in words is "one trillion, eleven billion, three hundred million, three hundred twenty-three thousand, eleven".
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