101130062235 has 16 divisors (see below), whose sum is σ = 161816703264. Its totient is φ = 53933165312.

The previous prime is 101130062233. The next prime is 101130062237. The reversal of 101130062235 is 532260031101.

It is an interprime number because it is at equal distance from previous prime (101130062233) and next prime (101130062237).

It is a cyclic number.

It is not a de Polignac number, because 101130062235 - 2¹ = 101130062233 is a prime.

It is not an unprimeable number, because it can be changed into a prime (101130062233) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 129409 + ... + 467981.

It is an arithmetic number, because the mean of its divisors is an integer number (10113543954).

Almost surely, 2^101130062235 is an apocalyptic number.

101130062235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

101130062235 is a deficient number, since it is larger than the sum of its proper divisors (60686641029).

101130062235 is a wasteful number, since it uses less digits than its factorization.

101130062235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 358494.

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 101130062235 its reverse (532260031101), we get a palindrome (633390093336).

The spelling of 101130062235 in words is "one hundred one billion, one hundred thirty million, sixty-two thousand, two hundred thirty-five".