1011312131321 has 2 divisors, whose sum is σ = 1011312131322. Its totient is φ = 1011312131320.

The previous prime is 1011312131311. The next prime is 1011312131371. The reversal of 1011312131321 is 1231312131101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 815562517225 + 195749614096 = 903085^2 + 442436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011312131321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011312131293 and 1011312131302.

It is not a weakly prime, because it can be changed into another prime (1011312131311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505656065660 + 505656065661.

It is an arithmetic number, because the mean of its divisors is an integer number (505656065661).

Almost surely, 2^{1011312131321} is an apocalyptic number.

It is an amenable number.

1011312131321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011312131321 is an equidigital number, since it uses as much as digits as its factorization.

1011312131321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1011312131321 its reverse (1231312131101), we get a palindrome (2242624262422).

The spelling of 1011312131321 in words is "one trillion, eleven billion, three hundred twelve million, one hundred thirty-one thousand, three hundred twenty-one".