Base | Representation |
---|---|
bin | 1001001100101010010100… |
… | …0011001110010001101011 |
3 | 1022210210201212102100201001 |
4 | 2103022211003032101223 |
5 | 2311143133224202311 |
6 | 33301523144135431 |
7 | 2062435410340135 |
oct | 223124503162153 |
9 | 38723655370631 |
10 | 10113122100331 |
11 | 3249a50860338 |
12 | 1173ba8167577 |
13 | 58488141a873 |
14 | 26d698c20055 |
15 | 1280eb19c4c1 |
hex | 932a50ce46b |
10113122100331 has 2 divisors, whose sum is σ = 10113122100332. Its totient is φ = 10113122100330.
The previous prime is 10113122100241. The next prime is 10113122100371. The reversal of 10113122100331 is 13300122131101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10113122100331 - 217 = 10113121969259 is a prime.
It is a super-2 number, since 2×101131221003312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10113122100299 and 10113122100308.
It is not a weakly prime, because it can be changed into another prime (10113122100371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056561050165 + 5056561050166.
It is an arithmetic number, because the mean of its divisors is an integer number (5056561050166).
Almost surely, 210113122100331 is an apocalyptic number.
10113122100331 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113122100331 is an equidigital number, since it uses as much as digits as its factorization.
10113122100331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 10113122100331 its reverse (13300122131101), we get a palindrome (23413244231432).
The spelling of 10113122100331 in words is "ten trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred thousand, three hundred thirty-one".
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