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101131313123 = 349128969153
BaseRepresentation
bin101111000101111100…
…1010101111111100011
3100200001000102000002202
41132023321111333203
53124104104004443
6114243055003415
710210061656331
oct1361371257743
9320030360082
10101131313123
1139986a98425
121772480956b
1396c9004ca9
144c753d0b51
15296d7087b8
hex178be55fe3

101131313123 has 4 divisors (see below), whose sum is σ = 101160285768. Its totient is φ = 101102340480.

The previous prime is 101131313117. The next prime is 101131313147. The reversal of 101131313123 is 321313131101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101131313123 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101131313095 and 101131313104.

It is not an unprimeable number, because it can be changed into a prime (101131313183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14481086 + ... + 14488067.

It is an arithmetic number, because the mean of its divisors is an integer number (25290071442).

Almost surely, 2101131313123 is an apocalyptic number.

101131313123 is a deficient number, since it is larger than the sum of its proper divisors (28972645).

101131313123 is an equidigital number, since it uses as much as digits as its factorization.

101131313123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28972644.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 101131313123 its reverse (321313131101), we get a palindrome (422444444224).

The spelling of 101131313123 in words is "one hundred one billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred twenty-three".

Divisors: 1 3491 28969153 101131313123