Base | Representation |
---|---|
bin | 101111000101111110… |
… | …1010001110011000001 |
3 | 100200001002100101220101 |
4 | 1132023331101303001 |
5 | 3124104340011023 |
6 | 114243133042401 |
7 | 10210103513314 |
oct | 1361375216301 |
9 | 320032311811 |
10 | 101132344513 |
11 | 39987632312 |
12 | 17725026401 |
13 | 96c92a6595 |
14 | 4c755bc97b |
15 | 296d85e1ad |
hex | 178bf51cc1 |
101132344513 has 2 divisors, whose sum is σ = 101132344514. Its totient is φ = 101132344512.
The previous prime is 101132344477. The next prime is 101132344519. The reversal of 101132344513 is 315443231101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63762815169 + 37369529344 = 252513^2 + 193312^2 .
It is an emirp because it is prime and its reverse (315443231101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101132344513 - 225 = 101098790081 is a prime.
It is a super-2 number, since 2×1011323445132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101132344519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566172256 + 50566172257.
It is an arithmetic number, because the mean of its divisors is an integer number (50566172257).
Almost surely, 2101132344513 is an apocalyptic number.
It is an amenable number.
101132344513 is a deficient number, since it is larger than the sum of its proper divisors (1).
101132344513 is an equidigital number, since it uses as much as digits as its factorization.
101132344513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 101132344513 its reverse (315443231101), we get a palindrome (416575575614).
The spelling of 101132344513 in words is "one hundred one billion, one hundred thirty-two million, three hundred forty-four thousand, five hundred thirteen".
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