Base | Representation |
---|---|
bin | 1001001100101010110000… |
… | …1110001001011001100011 |
3 | 1022210211001020210102221012 |
4 | 2103022230032021121203 |
5 | 2311143410023420301 |
6 | 33301543122451135 |
7 | 2062441401036044 |
oct | 223125416113143 |
9 | 38724036712835 |
10 | 10113242404451 |
11 | 324a00275a62a |
12 | 1174020503aab |
13 | 5848a0320034 |
14 | 26d6aabb88cb |
15 | 128106a12ebb |
hex | 932ac389663 |
10113242404451 has 2 divisors, whose sum is σ = 10113242404452. Its totient is φ = 10113242404450.
The previous prime is 10113242404403. The next prime is 10113242404519. The reversal of 10113242404451 is 15440424231101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10113242404451 - 222 = 10113238210147 is a prime.
It is a super-2 number, since 2×101132424044512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10113242404151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056621202225 + 5056621202226.
It is an arithmetic number, because the mean of its divisors is an integer number (5056621202226).
Almost surely, 210113242404451 is an apocalyptic number.
10113242404451 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113242404451 is an equidigital number, since it uses as much as digits as its factorization.
10113242404451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 10113242404451 its reverse (15440424231101), we get a palindrome (25553666635552).
The spelling of 10113242404451 in words is "ten trillion, one hundred thirteen billion, two hundred forty-two million, four hundred four thousand, four hundred fifty-one".
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