10113302113 has 4 divisors (see below), whose sum is σ = 10304119188. Its totient is φ = 9922485040.

The previous prime is 10113302099. The next prime is 10113302117. The reversal of 10113302113 is 31120331101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31120331101 = 59 ⋅527463239.

It can be written as a sum of positive squares in 2 ways, for example, as 7429233249 + 2684068864 = 86193^2 + 51808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10113302113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10113302117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95408458 + ... + 95408563.

It is an arithmetic number, because the mean of its divisors is an integer number (2576029797).

Almost surely, 2^10113302113 is an apocalyptic number.

It is an amenable number.

10113302113 is a deficient number, since it is larger than the sum of its proper divisors (190817075).

10113302113 is an equidigital number, since it uses as much as digits as its factorization.

10113302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190817074.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10113302113 its reverse (31120331101), we get a palindrome (41233633214).

The spelling of 10113302113 in words is "ten billion, one hundred thirteen million, three hundred two thousand, one hundred thirteen".