Base | Representation |
---|---|
bin | 1001001100101011000001… |
… | …0001101100011011101001 |
3 | 1022210211012222211011121101 |
4 | 2103022300101230123221 |
5 | 2311144024433140431 |
6 | 33301553553041401 |
7 | 2062443155253625 |
oct | 223126021543351 |
9 | 38724188734541 |
10 | 10113310443241 |
11 | 324a038101135 |
12 | 117403b256261 |
13 | 5848b1452c85 |
14 | 26d6b5c4a185 |
15 | 12810c9a2961 |
hex | 932b046c6e9 |
10113310443241 has 2 divisors, whose sum is σ = 10113310443242. Its totient is φ = 10113310443240.
The previous prime is 10113310443233. The next prime is 10113310443277. The reversal of 10113310443241 is 14234401331101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10059179767641 + 54130675600 = 3171621^2 + 232660^2 .
It is a cyclic number.
It is not a de Polignac number, because 10113310443241 - 23 = 10113310443233 is a prime.
It is not a weakly prime, because it can be changed into another prime (10113310443221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056655221620 + 5056655221621.
It is an arithmetic number, because the mean of its divisors is an integer number (5056655221621).
Almost surely, 210113310443241 is an apocalyptic number.
It is an amenable number.
10113310443241 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113310443241 is an equidigital number, since it uses as much as digits as its factorization.
10113310443241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 10113310443241 its reverse (14234401331101), we get a palindrome (24347711774342).
The spelling of 10113310443241 in words is "ten trillion, one hundred thirteen billion, three hundred ten million, four hundred forty-three thousand, two hundred forty-one".
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