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101133120312 = 233273713141399
BaseRepresentation
bin101111000110000000…
…0001111001100111000
3100200001010210211002200
41132030000033030320
53124110034322222
6114243201430200
710210113224160
oct1361400171470
9320033724080
10101133120312
1139988012174
121772533b360
1396c94b8733
144c757415a0
15296d963eac
hex178c00f338

101133120312 has 192 divisors, whose sum is σ = 323953344000. Its totient is φ = 27898940160.

The previous prime is 101133120281. The next prime is 101133120329. The reversal of 101133120312 is 213021331101.

101133120312 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 331 + 20 + 312 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2422189 + ... + 2463587.

It is an arithmetic number, because the mean of its divisors is an integer number (1687257000).

Almost surely, 2101133120312 is an apocalyptic number.

101133120312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101133120312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161976672000).

101133120312 is an abundant number, since it is smaller than the sum of its proper divisors (222820223688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101133120312 is a wasteful number, since it uses less digits than its factorization.

101133120312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41586 (or 41579 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 101133120312 its reverse (213021331101), we get a palindrome (314154451413).

It can be divided in two parts, 101133 and 120312, that added together give a triangular number (221445 = T665).

The spelling of 101133120312 in words is "one hundred one billion, one hundred thirty-three million, one hundred twenty thousand, three hundred twelve".