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10113400441481 is a prime number
BaseRepresentation
bin1001001100101011010110…
…1001000000101010001001
31022210211110021011112222112
42103022311221000222021
52311144221003111411
633302010530032105
72062445330241311
oct223126551005211
938724407145875
1010113400441481
11324a083991147
121174065418635
135848c6ca417c
1426d6c3b96441
1512811582db8b
hex932b5a40a89

10113400441481 has 2 divisors, whose sum is σ = 10113400441482. Its totient is φ = 10113400441480.

The previous prime is 10113400441477. The next prime is 10113400441493. The reversal of 10113400441481 is 18414400431101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8370947641081 + 1742452800400 = 2893259^2 + 1320020^2 .

It is a cyclic number.

It is not a de Polignac number, because 10113400441481 - 22 = 10113400441477 is a prime.

It is a super-2 number, since 2×101134004414812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10113400443481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056700220740 + 5056700220741.

It is an arithmetic number, because the mean of its divisors is an integer number (5056700220741).

Almost surely, 210113400441481 is an apocalyptic number.

It is an amenable number.

10113400441481 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113400441481 is an equidigital number, since it uses as much as digits as its factorization.

10113400441481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 32.

Adding to 10113400441481 its reverse (18414400431101), we get a palindrome (28527800872582).

The spelling of 10113400441481 in words is "ten trillion, one hundred thirteen billion, four hundred million, four hundred forty-one thousand, four hundred eighty-one".