Base | Representation |
---|---|
bin | 10110111111101101101111… |
… | …010111101111011111000101 |
3 | 111021002110022100001101001011 |
4 | 112333231233113233133011 |
5 | 101224000412113214301 |
6 | 555032553540202221 |
7 | 30205540031000413 |
oct | 2677555727573705 |
9 | 437073270041034 |
10 | 101135463413701 |
11 | 2a252344556832 |
12 | b414892099371 |
13 | 445805815a182 |
14 | 1ad8da81762b3 |
15 | ba5b7383da51 |
hex | 5bfb6f5ef7c5 |
101135463413701 has 16 divisors (see below), whose sum is σ = 105458581954048. Its totient is φ = 96900287299200.
The previous prime is 101135463413681. The next prime is 101135463413749. The reversal of 101135463413701 is 107314364531101.
It is a cyclic number.
It is not a de Polignac number, because 101135463413701 - 219 = 101135462889413 is a prime.
It is a super-3 number, since 3×1011354634137013 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101135463414701) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27965805 + ... + 31374466.
It is an arithmetic number, because the mean of its divisors is an integer number (6591161372128).
Almost surely, 2101135463413701 is an apocalyptic number.
It is an amenable number.
101135463413701 is a deficient number, since it is larger than the sum of its proper divisors (4323118540347).
101135463413701 is an equidigital number, since it uses as much as digits as its factorization.
101135463413701 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59341012.
The product of its (nonzero) digits is 90720, while the sum is 40.
The spelling of 101135463413701 in words is "one hundred one trillion, one hundred thirty-five billion, four hundred sixty-three million, four hundred thirteen thousand, seven hundred one".
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