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101140041441193 is a prime number
BaseRepresentation
bin10110111111110010000000…
…001111100001111110101001
3111021002220010101102021010221
4112333302000033201332221
5101224034301102104233
6555035032115210041
730206061340410346
oct2677620017417651
9437086111367127
10101140041441193
112a254283750627
12b41574b2a6921
134458607753291
141ad92c01937cd
15ba5d406e142d
hex5bfc803e1fa9

101140041441193 has 2 divisors, whose sum is σ = 101140041441194. Its totient is φ = 101140041441192.

The previous prime is 101140041441181. The next prime is 101140041441277. The reversal of 101140041441193 is 391144140041101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93940543597849 + 7199497843344 = 9692293^2 + 2683188^2 .

It is a cyclic number.

It is not a de Polignac number, because 101140041441193 - 213 = 101140041433001 is a prime.

It is not a weakly prime, because it can be changed into another prime (101140041411193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50570020720596 + 50570020720597.

It is an arithmetic number, because the mean of its divisors is an integer number (50570020720597).

Almost surely, 2101140041441193 is an apocalyptic number.

It is an amenable number.

101140041441193 is a deficient number, since it is larger than the sum of its proper divisors (1).

101140041441193 is an equidigital number, since it uses as much as digits as its factorization.

101140041441193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 34.

Adding to 101140041441193 its reverse (391144140041101), we get a palindrome (492284181482294).

The spelling of 101140041441193 in words is "one hundred one trillion, one hundred forty billion, forty-one million, four hundred forty-one thousand, one hundred ninety-three".