Base | Representation |
---|---|
bin | 101111000110001110… |
… | …0001011001101100011 |
3 | 100200001122120220022111 |
4 | 1132030130023031203 |
5 | 3124113423202003 |
6 | 114244022420151 |
7 | 10210232406064 |
oct | 1361434131543 |
9 | 320048526274 |
10 | 101140444003 |
11 | 39991164605 |
12 | 17727891657 |
13 | 96cab81091 |
14 | 4c766ca56b |
15 | 296e40de6d |
hex | 178c70b363 |
101140444003 has 2 divisors, whose sum is σ = 101140444004. Its totient is φ = 101140444002.
The previous prime is 101140443979. The next prime is 101140444019. The reversal of 101140444003 is 300444041101.
It is a strong prime.
It is an emirp because it is prime and its reverse (300444041101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101140444003 - 213 = 101140435811 is a prime.
It is not a weakly prime, because it can be changed into another prime (101140444043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50570222001 + 50570222002.
It is an arithmetic number, because the mean of its divisors is an integer number (50570222002).
Almost surely, 2101140444003 is an apocalyptic number.
101140444003 is a deficient number, since it is larger than the sum of its proper divisors (1).
101140444003 is an equidigital number, since it uses as much as digits as its factorization.
101140444003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 101140444003 its reverse (300444041101), we get a palindrome (401584485104).
The spelling of 101140444003 in words is "one hundred one billion, one hundred forty million, four hundred forty-four thousand, three".
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