Base | Representation |
---|---|
bin | 10010110101101100… |
… | …01111111011011011 |
3 | 222002212110202211101 |
4 | 21122312033323123 |
5 | 131203202330201 |
6 | 4351340212231 |
7 | 505431321511 |
oct | 113266177333 |
9 | 28085422741 |
10 | 10114105051 |
11 | 432016a906 |
12 | 1b6323a077 |
13 | c5252c15b |
14 | 6bd3864b1 |
15 | 3e2debd01 |
hex | 25ad8fedb |
10114105051 has 2 divisors, whose sum is σ = 10114105052. Its totient is φ = 10114105050.
The previous prime is 10114105019. The next prime is 10114105073. The reversal of 10114105051 is 15050141101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10114105051 - 25 = 10114105019 is a prime.
It is not a weakly prime, because it can be changed into another prime (10114102051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057052525 + 5057052526.
It is an arithmetic number, because the mean of its divisors is an integer number (5057052526).
Almost surely, 210114105051 is an apocalyptic number.
10114105051 is a deficient number, since it is larger than the sum of its proper divisors (1).
10114105051 is an equidigital number, since it uses as much as digits as its factorization.
10114105051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100, while the sum is 19.
Adding to 10114105051 its reverse (15050141101), we get a palindrome (25164246152).
It can be divided in two parts, 101141050 and 51, that added together give a palindrome (101141101).
The spelling of 10114105051 in words is "ten billion, one hundred fourteen million, one hundred five thousand, fifty-one".
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