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1011411403 = 5171195593
BaseRepresentation
bin111100010010001…
…110100111001011
32121111011000121121
4330102032213023
54032410131103
6244210020111
734030566202
oct7422164713
92544130547
101011411403
11479a083a2
12242877637
131317042b2
149847c239
155dbd76bd
hex3c48e9cb

1011411403 has 4 divisors (see below), whose sum is σ = 1011612168. Its totient is φ = 1011210640.

The previous prime is 1011411383. The next prime is 1011411437. The reversal of 1011411403 is 3041141101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011411403 - 217 = 1011280331 is a prime.

It is a super-2 number, since 2×10114114032 = 2045906052236856818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1011411103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92626 + ... + 102967.

It is an arithmetic number, because the mean of its divisors is an integer number (252903042).

Almost surely, 21011411403 is an apocalyptic number.

1011411403 is a deficient number, since it is larger than the sum of its proper divisors (200765).

1011411403 is an equidigital number, since it uses as much as digits as its factorization.

1011411403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200764.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1011411403 is about 31802.6949015331. The cubic root of 1011411403 is about 1003.7894231340.

Adding to 1011411403 its reverse (3041141101), we get a palindrome (4052552504).

The spelling of 1011411403 in words is "one billion, eleven million, four hundred eleven thousand, four hundred three".

Divisors: 1 5171 195593 1011411403