Base | Representation |
---|---|
bin | 1001001100101110011000… |
… | …0100110101010100011001 |
3 | 1022210220112220012220120001 |
4 | 2103023212010311110121 |
5 | 2311202402014311213 |
6 | 33302223314533001 |
7 | 2062504425233344 |
oct | 223134604652431 |
9 | 38726486186501 |
10 | 10114213041433 |
11 | 324a460648556 |
12 | 1174251597161 |
13 | 5849c6449147 |
14 | 26d75da8145b |
15 | 128161d441dd |
hex | 932e6135519 |
10114213041433 has 8 divisors (see below), whose sum is σ = 10243526404608. Its totient is φ = 9985077187344.
The previous prime is 10114213041421. The next prime is 10114213041481. The reversal of 10114213041433 is 33414031241101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10114213041433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10114213041833) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44262585 + ... + 44490502.
It is an arithmetic number, because the mean of its divisors is an integer number (1280440800576).
Almost surely, 210114213041433 is an apocalyptic number.
It is an amenable number.
10114213041433 is a deficient number, since it is larger than the sum of its proper divisors (129313363175).
10114213041433 is an equidigital number, since it uses as much as digits as its factorization.
10114213041433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88754543.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 10114213041433 its reverse (33414031241101), we get a palindrome (43528244282534).
The spelling of 10114213041433 in words is "ten trillion, one hundred fourteen billion, two hundred thirteen million, forty-one thousand, four hundred thirty-three".
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