10114220113 has 2 divisors, whose sum is σ = 10114220114. Its totient is φ = 10114220112.

The previous prime is 10114220099. The next prime is 10114220191. The reversal of 10114220113 is 31102241101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9957644944 + 156575169 = 99788^2 + 12513^2 .

It is a cyclic number.

It is not a de Polignac number, because 10114220113 - 2²¹ = 10112122961 is a prime.

It is not a weakly prime, because it can be changed into another prime (10114220213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057110056 + 5057110057.

It is an arithmetic number, because the mean of its divisors is an integer number (5057110057).

Almost surely, 2^10114220113 is an apocalyptic number.

It is an amenable number.

10114220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114220113 is an equidigital number, since it uses as much as digits as its factorization.

10114220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10114220113 its reverse (31102241101), we get a palindrome (41216461214).

The spelling of 10114220113 in words is "ten billion, one hundred fourteen million, two hundred twenty thousand, one hundred thirteen".