Base | Representation |
---|---|
bin | 111100010010010… |
… | …011011101011001 |
3 | 2121111012000211221 |
4 | 330102103131121 |
5 | 4032411300012 |
6 | 244210252041 |
7 | 34031011114 |
oct | 7422233531 |
9 | 2544160757 |
10 | 1011431257 |
11 | 479a21301 |
12 | 242887021 |
13 | 131710345 |
14 | 9848557b |
15 | 5dbdd507 |
hex | 3c493759 |
1011431257 has 2 divisors, whose sum is σ = 1011431258. Its totient is φ = 1011431256.
The previous prime is 1011431207. The next prime is 1011431261. The reversal of 1011431257 is 7521341101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 752350041 + 259081216 = 27429^2 + 16096^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011431257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011431207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505715628 + 505715629.
It is an arithmetic number, because the mean of its divisors is an integer number (505715629).
Almost surely, 21011431257 is an apocalyptic number.
It is an amenable number.
1011431257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011431257 is an equidigital number, since it uses as much as digits as its factorization.
1011431257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
The square root of 1011431257 is about 31803.0070433599. The cubic root of 1011431257 is about 1003.7959912178.
Adding to 1011431257 its reverse (7521341101), we get a palindrome (8532772358).
It can be divided in two parts, 101143 and 1257, that added together give a square (102400 = 3202).
The spelling of 1011431257 in words is "one billion, eleven million, four hundred thirty-one thousand, two hundred fifty-seven".
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