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10114403201083 is a prime number
BaseRepresentation
bin1001001100101111000101…
…1010001111000000111011
31022210221001011001000120001
42103023301122033000323
52311203244204413313
633302254230413431
72062512224454556
oct223136132170073
938727034030501
1010114403201083
11324a548a1a295
1211742a5201277
13584a2696944c
1426d77b02169d
151281738a7add
hex932f168f03b

10114403201083 has 2 divisors, whose sum is σ = 10114403201084. Its totient is φ = 10114403201082.

The previous prime is 10114403201047. The next prime is 10114403201087. The reversal of 10114403201083 is 38010230441101.

10114403201083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10114403201083 - 217 = 10114403070011 is a prime.

It is a super-2 number, since 2×101144032010832 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10114403201087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057201600541 + 5057201600542.

It is an arithmetic number, because the mean of its divisors is an integer number (5057201600542).

Almost surely, 210114403201083 is an apocalyptic number.

10114403201083 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114403201083 is an equidigital number, since it uses as much as digits as its factorization.

10114403201083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 10114403201083 its reverse (38010230441101), we get a palindrome (48124633642184).

The spelling of 10114403201083 in words is "ten trillion, one hundred fourteen billion, four hundred three million, two hundred one thousand, eighty-three".