1011440413153 has 2 divisors, whose sum is σ = 1011440413154. Its totient is φ = 1011440413152.

The previous prime is 1011440413133. The next prime is 1011440413163. The reversal of 1011440413153 is 3513140441101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 976683522529 + 34756890624 = 988273^2 + 186432^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011440413153 - 2⁵ = 1011440413121 is a prime.

It is a super-2 number, since 2×1011440413153² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011440413103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505720206576 + 505720206577.

It is an arithmetic number, because the mean of its divisors is an integer number (505720206577).

Almost surely, 2^{1011440413153} is an apocalyptic number.

It is an amenable number.

1011440413153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011440413153 is an equidigital number, since it uses as much as digits as its factorization.

1011440413153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 1011440413153 its reverse (3513140441101), we get a palindrome (4524580854254).

The spelling of 1011440413153 in words is "one trillion, eleven billion, four hundred forty million, four hundred thirteen thousand, one hundred fifty-three".