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10117153 = 20035051
BaseRepresentation
bin100110100110…
…000000100001
3201001000010101
4212212000201
510042222103
61000502401
7151665034
oct46460041
921030111
1010117153
115790192
12347aa01
132132ca7
1414b501b
15d4ca1d
hex9a6021

10117153 has 4 divisors (see below), whose sum is σ = 10124208. Its totient is φ = 10110100.

The previous prime is 10117147. The next prime is 10117157. The reversal of 10117153 is 35171101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 10117153 - 29 = 10116641 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10117153.

It is not an unprimeable number, because it can be changed into a prime (10117157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523 + ... + 4528.

It is an arithmetic number, because the mean of its divisors is an integer number (2531052).

Almost surely, 210117153 is an apocalyptic number.

It is an amenable number.

10117153 is a deficient number, since it is larger than the sum of its proper divisors (7055).

10117153 is an equidigital number, since it uses as much as digits as its factorization.

10117153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7054.

The product of its (nonzero) digits is 105, while the sum is 19.

The square root of 10117153 is about 3180.7472392506. The cubic root of 10117153 is about 216.2815330408.

Adding to 10117153 its reverse (35171101), we get a palindrome (45288254).

The spelling of 10117153 in words is "ten million, one hundred seventeen thousand, one hundred fifty-three".

Divisors: 1 2003 5051 10117153