Base | Representation |
---|---|
bin | 10111000000100100010010… |
… | …010110011110001101011011 |
3 | 111021022001111002211012021021 |
4 | 113000210102112132031123 |
5 | 101230430334234414401 |
6 | 555115521403423311 |
7 | 30213012312451111 |
oct | 2700442226361533 |
9 | 437261432735237 |
10 | 101194032341851 |
11 | 2a27516a152389 |
12 | b4240b8824b37 |
13 | 4460730279a87 |
14 | 1adbb62949ab1 |
15 | ba74506102a1 |
hex | 5c091259e35b |
101194032341851 has 2 divisors, whose sum is σ = 101194032341852. Its totient is φ = 101194032341850.
The previous prime is 101194032341827. The next prime is 101194032341881. The reversal of 101194032341851 is 158143230491101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101194032341851 - 243 = 92397939319643 is a prime.
It is a super-2 number, since 2×1011940323418512 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 101194032341798 and 101194032341807.
It is not a weakly prime, because it can be changed into another prime (101194032341881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50597016170925 + 50597016170926.
It is an arithmetic number, because the mean of its divisors is an integer number (50597016170926).
Almost surely, 2101194032341851 is an apocalyptic number.
101194032341851 is a deficient number, since it is larger than the sum of its proper divisors (1).
101194032341851 is an equidigital number, since it uses as much as digits as its factorization.
101194032341851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 43.
The spelling of 101194032341851 in words is "one hundred one trillion, one hundred ninety-four billion, thirty-two million, three hundred forty-one thousand, eight hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.116 sec. • engine limits •